问题描述：Given a binary matrix A, we want to flip the image horizontally, then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed. For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].
To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. For example, inverting [0, 1, 1] results in [1, 0, 0].
Example：
Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]] Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]] Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]. Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]先对行进行逆序，然后相当于1变0，0变1.
class Solution { public: vector<vector<int>> flipAndInvertImage(vector<vector<int>>& A) { vector<vector<int> > image; for(int n=0; n<A.size(); n++) { vector<int> row; for(vector<int>::iterator it = A[n].end(); it != A[n].begin(); ) { if(*(--it)) row.push_back(0); else row.push_back(1); } image.push_back(row); } return image; } };如果了解了算法的话，直接在逆序的时候进行转换就行了！O(∩_∩)O哈哈~
